-16t^2+400=336

Solution for -16t^2+400=336 equation:

-16t^2+400=336

We move all terms to the left:

-16t^2+400-(336)=0

We add all the numbers together, and all the variables

-16t^2+64=0

a = -16; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-16)·64
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-16}=\frac{-64}{-32}
=+2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-16}=\frac{64}{-32}
=-2
$